5x^2-61x+180=0

Solution for 5x^2-61x+180=0 equation:

5x^2-61x+180=0

a = 5; b = -61; c = +180;
Δ = b2-4ac
Δ = -612-4·5·180
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-11}{2*5}=\frac{50}{10}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+11}{2*5}=\frac{72}{10}
=7+1/5
$